Best and fastest way to convert CSV files into your MySQL database table using PHP.
The LOAD DATA INFILE statement reads rows from a text file into a table at very high speed.
First, create a file called csv2sql.php then follow the instructions below.
Instructions :
- Keep this
php file and yourcsv file in one folder - Create a table in
you mysql database to which you want to import - Run this
php script from your localhost server - Click on upload button
<html>
<head>
<title> csv2 sql</title>
<link rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css">
</head>
<body>
<br>
<h1> CSV to Mysql </h1>
<p> This Php Script Will Import very large CSV files to MYSQL database in a minute</p>
</br>
<form class="form-horizontal"action="csv2sql.php" method="post">
<div class="form-group">
<label for="mysql" class="control-label col-xs-2">Mysql Server address (or)<br>Host name</label>
<div class="col-xs-3">
<input type="text" class="form-control" name="mysql" id="mysql" placeholder="">
</div>
</div>
<div class="form-group">
<label for="username" class="control-label col-xs-2">Username</label>
<div class="col-xs-3">
<input type="text" class="form-control" name="username" id="username" placeholder="">
</div>
</div>
<div class="form-group">
<label for="password" class="control-label col-xs-2">Password</label>
<div class="col-xs-3">
<input type="text" class="form-control" name="password" id="password" placeholder="">
</div>
</div>
<div class="form-group">
<label for="db" class="control-label col-xs-2">Database name</label>
<div class="col-xs-3">
<input type="text" class="form-control" name="db" id="db" placeholder="">
</div>
</div>
<div class="form-group">
<label for="table" class="control-label col-xs-2">table name</label>
<div class="col-xs-3">
<input type="name" class="form-control" name="table" id="table">
</div>
</div>
<div class="form-group">
<label for="csvfile" class="control-label col-xs-2">Name of the file</label>
<div class="col-xs-3">
<input type="name" class="form-control" name="csv" id="csv">
</div>
eg. MYDATA.csv
</div>
<div class="form-group">
<label for="login" class="control-label col-xs-2"></label>
<div class="col-xs-3">
<button type="submit" class="btn btn-primary">Upload</button>
</div>
</div>
</form>
</div>
</body>
<?php
if(isset($_POST['username'])&&isset($_POST['mysql'])&&isset($_POST['db'])&&isset($_POST['username']))
{
$sqlname=$_POST['mysql'];
$username=$_POST['username'];
$table=$_POST['table'];
if(isset($_POST['password']))
{
$password=$_POST['password'];
}
else
{
$password= '';
}
$db=$_POST['db'];
$file=$_POST['csv'];
$cons= mysqli_connect("$sqlname", "$username","$password","$db") or die(mysql_error());
$result1=mysqli_query($cons,"select count(*) count from $table");
$r1=mysqli_fetch_array($result1);
$count1=(int)$r1['count'];
//If the fields in CSV are not seperated by comma(,) replace comma(,) in the below query with that delimiting character
//If each tuple in CSV are not seperated by new line. replace \n in the below query the delimiting character which seperates two tuples in csv
mysqli_query($cons, '
LOAD DATA LOCAL INFILE "'.$file.'"
INTO TABLE '.$table.'
FIELDS TERMINATED by \',\'
LINES TERMINATED BY \'\n\'
')or die(mysql_error());
$result2=mysqli_query($cons,"select count(*) count from $table");
$r2=mysqli_fetch_array($result2);
$count2=(int)$r2['count'];
$count=$count2-$count1;
if($count>0)
echo "Success";
echo "<b> total $count records have been added to the table $table </b> ";
}
else{
echo "Mysql Server address/Host name ,Username , Database name ,Table name , File name are the Mandatory Fields";
}
?>The fastest way to import a CSV file is to use Mysql LOAD DATA command.
Reference: https://dev.mysql.com/doc/refman/5.7/en/load-data.html
0 Comments